Winter 2011 Nautical Deck Answers Part—2

Excerpt from U.S. Coast Guard Proceedings of the Marine Safety & Security Council magazine. Nautical Deck Queries Answers Part—2.

1. A vessel of not more than 65 feet in length must have a collision bulkhead if it carries more than_______.

A. 6 passengers

Incorrect answer.

B. 12 passengers

Incorrect answer.

C. 36 passengers

Incorrect answer.

D. 49 passengers

Correct answer. As per 46 CFR 179.210, a vessel of not more than 19.8 meters (65 feet) in length

must have a collision bulkhead if it:

1) Carries more than 49 passengers;

2) Operates on exposed waters;

3) Is of more than 12.2 meters (40 feet) in length and operates on partially protected

waters; or

4) Is constructed of wood on or after March 11, 2001, and operates in cold water.

2. How many portable fire extinguishers are required to be located inside the machinery spaces of a small passenger vessel?

A. None are required.

Correct answer. None are required inside the machinery space. A minimum of one portable fire extinguisher is required, of CG class B-II, C-II, to be located just outside the machinery space exit. See 46 CFR 181.500, Table 181.500(a).

B. One B-I, C-I is required.

Incorrect answer.

C. One B-II, C-II is required.

Incorrect answer.

D. One B-II is required.

Incorrect answer.

3. Which statement is true concerning the placard entitled “Discharge of Oil Prohibited”?

A. It is required on all vessels.

Incorrect answer.

B. It may be located in a conspicuous place in the wheelhouse.

Incorrect answer.

C. It may be located at the bilge and ballast pump control station.

Correct answer. As per 33 CFR 155.450, a ship (except a ship of less than 26 feet in length) must have a placard of at least five by eight inches made of durable material fixed in a conspicuous place in each machinery space, or at the bilge and ballast pump control station, stating the following: “Discharge

of Oil Prohibited.”

D. All of the above.

Incorrect answer.

4. A cargo of canned foodstuffs is packed in cartons. Each carton is 36 cubic feet and weighs 380 pounds. What is the stowage factor of the cargo?

A. 9.5

Incorrect answer.

B. 62

Incorrect answer.

C. 212

Correct answer. The formula for stowage factor computation is cubic capacity divided by weight in long tons.

1 long ton is equal to 2240 lbs.

The weight of the cargo is given in pounds and must be converted to long tons.

380lbs / 2240lbs = .1696 long tons

Stowage factor = 36 cubic feet / .1696 long tons = 212.26.

D. 237

Incorrect answer.

Full article is available at http://www.uscg.mil/proceedings/winter2010-11/

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